Question

2. Lines AB and CD are parallel
. MN intersects AB and CD at points P and Q, respectively. Find the
value of ZBPQ, ZPQD and ZPQC.
MA
(6x + 35)
B
P
(4x + 15)°
Q
D​

Answer 1

GIVEN:

• AB&CD Parallel

• MN intersects at P Q.

• GIVEN angles:

• BPQ=6x+35
• PQD=4x+15

NOW:

• BPQ+PQD=180(interiror angle=180)

• 6x+35+4x+15=180

• 10x+40=180

• 10x=180-40

• 10x=140

• x=140/10

• x=14

BPQ:

• 6×14+35=119

PQD:

• 4×14+15=71

PQC:

• BPQ=PQC=119 (ALTERNATE INTERIOR ANGLES =)

• Therefore,PQC=119

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