Question

2 log10 8+log10 36-log 10(1.5) - 3 log 10 2

Answer 1

$2 log(8) + log(36) - log(1.5) - 3 log(2)$
We know that
$log(x) + log(y) = log(xy) \\ log(x) - log(y) = log( \frac{x}{y} )$
Thus the question reduces to
$log( {8}^{2} ) + log(36) - log(1.5) - log({2}^{3})$
$log(64 \times 36) - log( 12) \\ = log(64 \times 36 \times \frac{1}{12} ) \\ = log(64 \times 3) \\ = log(192)$

Answer 2

Answer:

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Step-by-step explanation:

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