Math, asked by sunilkumarmishra69, 3 months ago

2 (m-2)-3 (m-3)=5 (m-5)-4 (m-8)​

Answers

Answered by dezisantosh
24

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Answered by Flaunt
38

\huge\bold{\gray{\sf{Answer:}}}

Explanation:

 =  > 2(m - 2) - 3(m - 3) = 5(m - 5) - 4(m - 8)

 =  > 2m - 4 - 3m + 9 = 5m - 25 - 4m + 32

 =  >  - m + 5 = m + 7

 =  >  - m - m = 7 - 5

 =  >  - 2m = 2

 =  > m =  \frac{2}{ - 2}  =  - 1

\bold{\boxed{\boxed{\red{m=-1}}}}

Concept used

When we divide any or mutiply any negative value with positive value the resultant would be in negative.

\huge\mathbb{CHECK}

2 (m-2)-3 (m-3)=5 (m-5)-4 (m-8)

 =  > 2( - 1 - 2) - 3( - 1 - 3) = 5( - 1 - 5) - 4( - 1 - 8)

 =  > 2 \times  - 3 - 3 \times  - 4 = 5 \times  - 6 - 4 \times  - 9

 =  >  - 6 + 12 =  - 30 + 36

6 = 6

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