Math, asked by manisha3530, 10 months ago

2^m+n/2^n-m=16 and a =2 ^1/10find the value of a^4m+n-p/(a^6m-n+p)^-1​

Answers

Answered by ansu2304
1

Answer:

2^m+n/2^m-n=16 Equating the power as base same

=2^m+n-(m-n) =16

=2^m+n-m+n=16

=2^2n=2^4

=2n=4

=n=4/2

=n=2

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