Question

2 M solution is formed when 10 gm solute is
present in 100 ml solution. Calculate the molarity
of solution which is formed by the dissolution of
25 gm solute in 500 ml solution​

Answer 1

Answer:

M = 1 M

Explanation:

2 = 10 / w * 0.1     ( V = 0.1 L  ;  w ---> molecular weight of solute )

w = 50 g

secondly ,

      M = 25 / 50*0.5   ( V=0.5L )

      M = 1 M

Answer 2

Answer:

Molarity of solution is 1M

Explanation:

Given that,

The molarity of solution=2M

The weight of solute=10gm

The volume of solution=100ml

The Molecular weight of solute=?

We know that,molarity is found using relation,

$M = \frac{wt.of \: solute}{molecular \: wt.of \: solute} \times \frac{1000}{volume(in \: ml)}$

Let the molecular weight of solute be x g/mol

Therefore substituting values in above relation,we get

$2 = \frac{10}{x} \times \frac{1000}{100} = = > x = 50g/mol$

Therefore,molecular weight of this solute is 50g/mol

Now in the given situation,

Weight of solute=25gm

Volume of solution=500ml

Therefore molarity can be found as

$M = \frac{25g}{50gmol {}^{ - 1} } \times \frac{1000}{500} = 1M$

Therefore molarity of solution is 1M

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