Question

2 m wide road runs around a circular park whose circumference is 88 m. Find the cost of fencing the outer boundary of the road at the rate of ₹ 35 per m​

Answer 1

Answer:

6597.5

Step-by-step explanation:

as the circumference is 88

2πr= 88

2*22/7*r= 88

r = 88*7/2*22

r = 28

as the r is 28 and the road is 2 m wide so the total r will be 30

c= 2πr

2*22/7*30

= 188.5 m

so the cost is 188.5*35

= 6597.5

Answer 2

Step-by-step explanation:

given ....

2m outer radius...

circumference=88m....

cost of fencing is ₹35per m

solution.......................................

circumference of circle=2πr

so, 2πr=88

2×22×r=88×7

44r=616

r=616/44

r=14

since...

road is 2m wide and fence to be done to outer side....

so,it's new radius =2+14

r=16m....

now it's circumference will be...

2πr=2×22/7×16..

44/7×16.....

=704/7......

=100.5714m....

so...........

cost of fencing=100.5714×35..

=₹3519.999......(answer)