Question

2 men and 5 boys can do a price of work in 4 days, while 4 men and 4 boys can do it in 3 days. how long would it take one man alone to do it how many days would it take one boy alone to do it​

Answer 1

Answer:

Let the amount of work done by a Man alone in a day be M and by a Boy alone be B

Given, 2 men and 5 boys together can finish a piece of work in 4 days

Amount of work they can do in one day 2M+5B =

$\frac{4}{1}$

-- (1)

Similarly, 3M+6B=

$\frac{3}{1}$

--- (2)

Solving equations (1) and (2), we get B=

$\frac{36}{1}$

Substituting B in equation (2), we get M=

$\frac{18}{1}$

Hence, one man alone will take 18 days to do the work and one boy will take 36 days.

Answer 2

Answer:

Correct option is

A

18 days and 36 days

Let the amount of work done by a Man alone in a day be M and by a Boy alone be B

Given, 2 men and 5 boys together can finish a piece of work in 4 days

Amount of work they can do in one day 2M+5B =41 -- (1)

Similarly, 3M+6B=31 --- (2)

Solving equations (1) and (2), we get B=361

Substituting B in equation (2), we get M=181

Hence, one man alone will take 18 days to do the work and one boy will take 36 days.

Step-by-step explanation:

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