2 men and 5 boys can together finish a work in 4 days while 3 men and 6 boys can finish it in 3 days, find the time taken by one man alone to finish the work,
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Let one man complete the work in 1/x days and one boy completes the work in 1/y days.
Now, 2 men and 5 boys can finish a piece of job in 4 days
⇒ 2x + 5y = 1/4
⇒ 8x + 20y = 1 .........(1)
Also, 3 men and 6 boys finish it in 3 days
⇒ 3x + 6y = 1/3
⇒ 9x + 18y = 1 ........(2)
Now, solving the equations (1) and (2)
We get 1/x = 18 and 1/y = 36
So, Total time taken by one man to complete the job = 18 days
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