2 men and 5 boys together can finish a piece of work in 4 days, while 3 men and 6 boys can finish<br />it in 3 days. Find the time taken by 1 man alone to finish the work and than taken by 1 boy alone .
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Let the amount of work done by a Man alone in a day be M and by a Boy alone be B
Given, 2 men and 5 boys together can finish a piece of work in 4 days
Amount of work they can do in one day 2M + 5B = 1 ÷ 4 --- (1)
Similarly, 3M + 6B = 1 ÷ 3 --- (2)
Solving equations (1) and (2), we get B = 1 ÷ 36
Substituting B in equation (2), we get M = 1 ÷ 18
Hence, one man alone will take 18 days to do the work and one boy will take 36 days.
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