Question

2 milk containers contains 398 l and 436 l of milk. the milk is to be transferred to another container with the help of a drum. while transferring to another container 7 l and 11 l of milk is left in both the containers. find the maximum capacity of the drum.

Answer 1

volume V1 = 398 liters

V2 = 436 Litres

     a drum of capacity D litres is used to transfer the milk to other containers.  When we transfer milk, we transfer D litres, 2D litres, 3 D , 4D etc. amounts.  If there is any milk left out, that will be a fraction of the capacity of the drum.

 

  let m and n be integers.

   V1 = 398 = m * D + 7      =>    m * D = 391 = 17 * 23

   V2 = 436 = n * D + 11    =>    n * D = 425  =  5 * 5 * 17

        Looking at both equations above,  D = 17  , as only 17 occurs in both.

 

answer is 17 liters.

 

Hope This Helps :)

Answer 2

Answer:

$\bf\Large\color{Orange}{Hey...Friend}$

refer to the above image