Question

2 mole of an ideal gas expanded isothermally and reversible from one litre 210 litres at 300 kelvin what is the enthalpy change

Answer 1

Answer:

H=E+PV

ΔH=ΔE+Δ(PV)

Since, PV=nRT

So, ΔH=ΔE+nRΔT

ΔT=0 and ΔE=0

∴ΔH=0

Enthalpy change for an ideal gas in an isothermal and reversible process is Zero.