2 mole of ideal gas at 27ºC temp. is expanded reversibly from 2 lit. to 20 lit. Find entropy change (R = 2 cal/mol K) : -
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Answer:
9.212 cal/K
Explanation:
n = 2 moles ; v1 = 2 L ; v2 = 20 L
ΔS = nR × 2.303㏒ (v2/v1) cal/K
= 2×2×2.303×㏒(20/2) cal/K
= 9.212 × ㏒10 cal/K
= 9.212 cal/K
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