Question

2 mole of N2 is reacted with 4 moles of H2 to produce ammonia . Mass of ammonia produced is

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Answer 1

Answer :-

45.39 grams of ammonia is produced .

Explanation :-

N₂ + 3H₂ → 2NH₃

From the balanced equation, we can understand that 1 mole of N₂ combines with 3 moles of H₂ , to form ammonia gas .

So, 2 moles of N₂ will combine with :-

= (2 × 3)

= 6 moles of H₂

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But here we are given only 4 moles of H₂ . Thus, H₂ is the limiting reagent and will control the amount of product .

Now, again from the balanced equation :-

∵ 3 moles of H₂ → 2 moles of NH₃

∴ 4 moles of H₂ → 2.67 moles of NH₃

Mass of ammonia formed :-

= Number of moles × Molar mass

= 2.67 × 17

= 45.39 g

Answer 2

Given :-

2 moles of N2 is reacted with 4 moles of H2 to produce ammonia.

To Find :-

The Mass of ammonia produced is

Solution :-

Balanced equation

In words - Nitrogen + Hydrogen ⇒ Ammonia

N₂ + 3H₂ ⇒ 2NH₃

1 mole(nitrogen) + 3 moles(hydrogen) make 2 moles of Ammonia

2 moles of nitrogen = 2 × 3 = 6 moles of hydrogen

3 moles of hydrogen = 2 moles of ammonia

1 mole of hydrogen = 2/3 mole of ammonia

4 moles of hydrogen = 2/3 × 4 = 8/3 moles

Mass = Molar mass × Number of moles

Mass = 17 × 8/3

Mass = 136/3

Mass = 45.33