Question

2 moles of a gas are present in a vessel at 270

C. If the pressure of a gas is 380 mm of Hg,

calculate the volume of the gas. ( R = 0.0821 L atm K

-1 mol-1​

Answer 1

Answer:

The volume of the gas will be 178.32 L.

Explanation:

According to ideal gas law:

PV = nRT

P = pressure

V = Volume

n = number of moles

R = gas constant = 0.0821 L atm/K/mol

Given that:

P = 380 mm Hg = 0.5 atm

n = 2 moles

T = 270 °C = 543 K

Substituting the above values:

V = $\frac{2 * 0.0821*543}{0.5}$

  = 178.32 L

Therefore the volume of the gas will be 178.32 Litres.