2 moles of helium is heated at constant pressure from 0°C to 50°C. find enthalpy change.
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3
Answer:
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Explanation:
As it is a constant pressure process, using Charles law we get
T
V
=constant. Thus for a threefold increase in volume we get threefold increase in temperature. Thus we get the final temperature as 3(273)=819K. Thus ΔT=819−273=546K.
Now as helium is a diatomic molecule, its degree of freedom f is 5. Ths we get C
p
for it as (1+
2
f
)R=(1+
2
5
)R=
2
7
R.
Thus heat transferred will be given as ΔQ=nC
p
ΔT
or
ΔQ=1(
2
7
)(1.987)(546)= 361 cal
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Explanation:
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