2 moles of nh3 when put into priviously evacuated vessel (1 l) ,partially dessociates into n2 and h2 .If at equilibrim 1 mole of nh3 is present the equilibrium constant is
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no of moles
at t=0 2
at t=teq 2-x 3x/2 x/2
but as per the question,
2-x =1 ---> x = 1
thus, 1 3/2 ½
equilibrium constant= [H2]3 × [N2]/[NH3]2
substituting values.. we get,
equilibrium constant= 33/23 × 1/2=27/16
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