Question

An electric bulb is rated as 22w and 220v.Find the rasistancce of this bulb

Answer 1

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$Power =VI\\ \\ P = \frac{V^2}{R}\\ \\ R=\frac{V^2}{P}\\ \\ R=\frac{220 \: ^2}{22}\\ \\ \boxed{R=2200 \: \Omega}$

Answer 2

Answer:-

Let V 1 b the power:-

P= RV²

R= PV²

R= 220²/22

•°•R=2200