2 moles of nitrogen atoms at 273k temperature and 1 atmosphere pressure occupies a volume of how much litre
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PV = nRT
V = nRT/P
V = 2*R*273/1
V = 2* 0.082 * 273 /1
V= 44.772 L
Value of R is taken 0.082 as pressure is in atmosphere
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V = nRT/P
V = 2*R*273/1
V = 2* 0.082 * 273 /1
V= 44.772 L
Value of R is taken 0.082 as pressure is in atmosphere
Thank You
Hope this answers your question
If you don’t mind please mark it as Brainliest answer
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