Question

2^n+2÷2^n+2-2(2)^n
please solve it​

Answer 1

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$\frac{ {2}^{n} + 2}{ {2}^{n} + 2 - 2 {(2)}^{n} } \\ = \frac{ {2}^{n} + 2}{ {2}^{n} + 2 - 2 .{2}^{n} } \\ = \frac{ {2}^{n} (1 + 2)}{ {2}^{n}(1 + 2 - 2 \times 1) } \\ = \frac{ {2}^{n} (1 + 2)}{ {2}^{n}(1 + 2 - 2) } \\ = \frac{(1 + 2)}{(1 + 2 - 2)} \\ = \frac{3}{1} \\ = 3$

Answer 2

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$$\begin{lgathered}\frac{ {2}^{n} + 2}{ {2}^{n} + 2 - 2 {(2)}^{n} } \\ = \frac{ {2}^{n} + 2}{ {2}^{n} + 2 - 2 .{2}^{n} } \\ = \frac{ {2}^{n} (1 + 2)}{ {2}^{n}(1 + 2 - 2 \times 1) } \\ = \frac{ {2}^{n} (1 + 2)}{ {2}^{n}(1 + 2 - 2) } \\ = \frac{(1 + 2)}{(1 + 2 - 2)} \\ = \frac{3}{1} \\ = 3\end{lgathered}$$