2 natural number differ by 4 and the sum of the square is 58 find the numbers
Answers
Answered by
2
7 and 3 .
The difference between two
= 7-3
= 4
7^2= 7*7 = 49
3^2= 3*3 = 9
Sum of their squares = 49+9
= 58
Therefore, the two numbers are 7 and 3
The difference between two
= 7-3
= 4
7^2= 7*7 = 49
3^2= 3*3 = 9
Sum of their squares = 49+9
= 58
Therefore, the two numbers are 7 and 3
Answered by
2
let the numbers be x and y
x-y=4
therefore, x=y+4
x²+y²=58
(y+4)²+y²=58
y²+8y+16+y²=58
2y²+8y=42(58-16)
2(y²+4y-21)=0
y²+4y-21=0/2
y²+7y-3y-21=0
y(y+7)-3(y+7)=0
(y+7)(y-3)=0
therefore,y=-7,3
as the nos are natural, y=3
x=3+4=7
x=7
y=3
x-y=4
therefore, x=y+4
x²+y²=58
(y+4)²+y²=58
y²+8y+16+y²=58
2y²+8y=42(58-16)
2(y²+4y-21)=0
y²+4y-21=0/2
y²+7y-3y-21=0
y(y+7)-3(y+7)=0
(y+7)(y-3)=0
therefore,y=-7,3
as the nos are natural, y=3
x=3+4=7
x=7
y=3
RUTVI1:
your welcome
your name
Niki
nice name
age
urs??
14
and urs
16....
i meant what is ur name??
Similar questions