Question

2. Nature, position of the image and type of lens used when the magnification is (-1).

A) Real, inverted and enlarged image beyond 2F2 obtained from concave lens.

B) Virtual , erect and diminished image at 2F1 obtained from concave lens.

C) Real , erect and enlarged image at 2F2 obtained from convex lens

D) Real, inverted and similar sized image at 2F2 obtained from convex lens.​

Answer 1

Answer:

1. Magnification = Image sizeObject size According to new Cartesian sign convention, size of height of real and inverted image is considered negative and ...
2. CONCEPT: Lens: The transparent curved surface which is used to refract the light and make an image of any object placed in front of it is ...
3. Infinity, At F2, Virtual and Erect, Highly Diminished ... At 2 F1, At 2F2, Real and Inverted, Same size. 4.A virtual, erect and enlarged image is formed at the same side of lens, when an object is placed between principal focus, F1 and optical centre, O of a convex lens. Properties of Image: Image is enlarged, virtual and erect. 4.A diminished, real and inverted image is formed between principal focus, F2 and centre of curvature, C2 at the opposite side when an object is placed beyond ...

Answer 2

Answer:

2.Nature position of the image and type of lens used when the magnification is (-1) *

1 point

A.Real,inverted and enlarged image beyond 2F2 obtained from concave lens

B.Virtual ,erect and diminished image at 2F1obtained from concave lens

C.Real ,erect and enlarged image at 2F2 obtained from convex lens

D.Real ,inverted and similar sized image at 2F2 obtained from convex lens