Question

2 non reacting gases G1 (of molar mass M1) and G2 (of molar mass M2) were taken in their weight ratio 2:3 in a closed container at constant temperature. If the pressure of the gas G1 was just double of the gas G2 in the mixture. Then M1/M2 will be

Answer 1

Given :
Weight of ratios of two non reacting gases of G1 and G2 =2: 3
m1/m2=2/3
pressure of G1 doubles of gas G2
p1=2p2
p1/p2= 2/1
according to ideal gas equation:
Pv=nRT
n=number of moles=mass/ molar mass
n1/n2=m1/M1/m2/M2
since pressure is directly proportional to n
p1/p2=n1/n2
2/1=m1/M1/m2/M2
2/1=2/M1/1/M2
2/1=2M2/M1
therefore, M1/M2 = 1/3