2 number are such that the ratio between them is 3 ratio 5 if each is increased by 10 the ratio between them 5 ratio 7 find the original number
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Heya mate,
Your answer is in the attachment.
#kevin
Hope it will help you..
Your answer is in the attachment.
#kevin
Hope it will help you..
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Answered by
4
let the two numbers be x & y
x/y = 3/5
x = 3y/5 (eq.1)
when each no. is increased by 10
x+10/y+10 = 5/7
7x + 70 = 5y + 50 (eq.2)
7 x 3y/5 + 70 = 5y + 50
(21y + 350)/5 = 5y + 50
21y + 350 = 25y + 250
4y = 100
y = 25
by putting value of y in eq.2
7x +70 = 125 + 50
7x = 105
x = 105/7
x = 15
x/y = 3/5
x = 3y/5 (eq.1)
when each no. is increased by 10
x+10/y+10 = 5/7
7x + 70 = 5y + 50 (eq.2)
7 x 3y/5 + 70 = 5y + 50
(21y + 350)/5 = 5y + 50
21y + 350 = 25y + 250
4y = 100
y = 25
by putting value of y in eq.2
7x +70 = 125 + 50
7x = 105
x = 105/7
x = 15
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