Question

2 numbers are in the ratio 4:5. If difference of their cubes is 61. Find the numbers

Answer 1

let the ratio be X

then

number = 4x and 5x

according to question

(5x)^3 - (4x)^3 = 61

x^3( 125 - 64 ) = 61

61x^3 = 61

X = 1

so

both number is

4 and 5

Answer 2

Answer:

$let \: the \: number \: be \: x$

$given \: ratio =$

4:5

$4x \: and \: 5x$

• according to the question:

$5x ^{3} - 4x ^{3} = 61$

$x ^{3} (125 - 64) = 61$

$61x^{3} = 61$

$x ^{3} = \frac{61}{61}$

$x = 1$

• There fore the numbers are
• 4 and 5