Question

2. p²q2_12 pqr + 36 r², when p=4 q=7 r=5

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Answer 1

ANSWER

From the figure we have,

A=(2−2+3​,24−1​)=(21​,23​)

B=(27+3​,24−2​)=(15​,11​)

C=(2−2+7​,2−2−1​)=(25​,2−3​)

Using the formula of equation of line,

equation of the median PC is given by

y−4=3−5/24+3/2​(x−3)

⟹11x−y−29=0

 equation of the median RB is given by

y+1=5+21+1​(x+2)⟹2x−7y−3=0

 equation of the median AQ is given by

y+1=7−1/2−2−3/2​(x+2)⟹7x+13y−23=0

Answer 2

Answer:

hi friend

Step-by-step explanation:

here's your answer

p=4,q=7,r=5

p^2q^2-12 pqr +36 r ^2

4^27^2-12 4×7×5+36 (5^2)

16(49)-124×7×5+36 (10)

784(140)-12+360

109748+360

110108

I hope you understand