Question

x^100+61 divide by x-1 then what is remainder​

Answer 1

Question :-

• x^100+61 divide by x-1 then what is remainder?

Solution :-

$let \: \: f(x) = x {}^{100} + 61 \\ and \: \: g(x) = x - 1 \\ \\ hence, \\ \: \: \: g(x) = 0 \\ \: \: x - 1 = 0 \\ \: \: \: x = 1 \\ \\ as, \: \: f(x) = x {}^{100} + 61 \\ \\ so, \: \: f(1) = (1) {}^{100} + 61 \\ \: \: \: \: \: \: f(1) = 62 \: \: \: \: \: (remainder) \: \: \: \: \: ans$