2 paper screens are separated by a distance of 100 cm. a bullet pierces a and then b. the hole in b is 10 cm below hole a. if the bullet strikes the screen horizontally, find horizontal velocity
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Let, x=100 m and h=10cm
Using equation of motion we can calculate the time of the motion as,
h=ut+12gt2
Assuming initial velocity to be zero and g=10 m/s2, we get,
t=2hg‾‾‾√t=2×10 cm10 m/s2‾‾‾‾‾‾‾√t=2×0.1 m10 m/s2‾‾‾‾‾‾√t=0.14 s
Now, again using equation of motion as,
x=vtor,v=xt
we get,
v=100 m0.14 sv=707.11 m/s
Using equation of motion we can calculate the time of the motion as,
h=ut+12gt2
Assuming initial velocity to be zero and g=10 m/s2, we get,
t=2hg‾‾‾√t=2×10 cm10 m/s2‾‾‾‾‾‾‾√t=2×0.1 m10 m/s2‾‾‾‾‾‾√t=0.14 s
Now, again using equation of motion as,
x=vtor,v=xt
we get,
v=100 m0.14 sv=707.11 m/s
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