Question

Line segment DF intersects the side AC of a triangle ABC at the point E such that E is the midpont of CA and angle AEF=angle AFE. Prove that BD/CD=BF/CE

Answer 1

prove that BD/CD = BF/CE


Draw CG || DF In ΔBDF

CG || DF

∴ BD/CD = BF/GF   .............(1)  BPT

In ΔAFE

∠AEF=∠AFE

⇒AF=AE

⇒AF=AE=CE..............(2)

In ΔACG

E is the mid point of AC

⇒ FG = AF

∴ From (1) & (2)

BD/CD   =  BF/CE

Answer 2

Answer:

Step-by-step explanation:

Please mark it brainliest