2 parallel chords AB and CD are of length 16 cm and 24 cm are the drawn of opposite of the centre. If the radius of the circle is 10cm. find the distance between the parallele chords
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Answer:
r2=x2+(5)2
also, r2=(17−x)2+(12)2
So, x2+(5)2=(17−x)2+(12)2
x2+25=(17−x)2+144
⇒x=12
∴r2=144+25=169
⇒r=13cm
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