Question

2 parallel chords of length 80cm and 18cm are drawn on the same side of the center of the circle of radius 41cm. Find the distance between the chord

Answer 1

Answer:

Step-by-step explanation:

AE =40cm

CF=9cm

using Pythagoras theorem in triangle AEO

AO2=AE2+EO2

(41)2=(40)2+EO2

1681=1600+EO2

1681-1600=EO2

81=EO2

9=EO

using Pythagoras theorem in triangle OCF

OC2=CF2+OF2

1681=(9)2+OF2

1681=81+OF2

1681-81=OF2

1600=OF2

40=OF

OC=40-9

OC=31cm