Question

2. Phenol associates in benzene as
CH,OH =* (CH,OH),
If degree of association of phenol is 40%. van't
Hoff factor i is :-
(1) 1 (2) 0.8 (3) 1.4 (4) 0.6​

Answer 1

The option 2 is correct.

Explanation:

Degree of association and van't Hoff factor (i) given by::

$\alpha =\frac{(1-i)n}{n-1}$

Where :

n = simple molecules of solute in solvent

We have :

Degree of association of phenol= 40% = 0.40

$C_6H_5OH\rightarrow \frac{1}{2} (C_6H_5OH)_2$

$2C_6H_5OH\rightarrow (C_6H_5OH)_2$

n = 2

$0.40=\frac{(1-i)2}{2-1}$

i = 0.8

The option 2 is correct.

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Answer 2

Answer:

Answer of the above question is 0.8.