Question

2. | Plot the points (aqu) ajven in the Lollowing
table on the place choosing wuitable was
of distance of the axes .
2 -2 -1 JO13
I y lort -1.251 3. -1......... ​

Answer 1

Answer:here you go

Step-by-step explanation:

Answer 2

$\huge\star{\purple{\underline{\underline{\mathfrak{Explanation:}}}}}$

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The points to plotted on the(x,y) are:

• (-2,8)

• (-1,7)

• (0,-1.25)

• (1,3)

• (3,-1)

On the graph mark X-axis and Y-axis. Mark the meeting point as O.

Now, Let 1 unit = 1 cm.

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$\huge{\pink\leadsto}$ (-2,8): II- Quadrant, Meeting point of the imaginary lines that starts from 2 units to the left of origin O and from 8 units above the origin O

$\huge{\blue\leadsto}$ (-1,7): II- Quadrant, Meeting point of the imaginary lines that starts from 1 units to the left of origin O and from 7 units above the origin O

$\huge{\purple\leadsto}$ (0,-1.25): On the y-axis, 1.25 units to the bottom of origin O

$\huge{\orange\leadsto}$ (1,3): I- Quadrant, Meeting point of the imaginary lines that starts from 1 units to the right of origin O and from 3 units above the origin O

$\huge{\green\leadsto}$ (3,-1): IV- Quadrant, Meeting point of the imaginary lines that starts from 3 units to the right of origin O and from 1 unit below the origin O