2 point charges of +16 microcoulomb and -9 microcoulomb are placed 8 cm apart in air. Determine the position of the point where resultant electric field is 0 ( zero).
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⏩⏩⏩we have two points A and B of charge 16 and 9 and distance between them is 8
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use 9×10^9 ×q1 ×q2 / r^2
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9×10^9 ×16 ×-9 /8^2
♣♣
9×10^9 × -36
= -3.24 e 11
:::: : : : : : : : : : : : : :
Hope you satisfied with my answer
please mark as brainlest as if it helps you
: : : : : : : : : : : : : : : : :
⏩⏩⏩we have two points A and B of charge 16 and 9 and distance between them is 8
♣♣
use 9×10^9 ×q1 ×q2 / r^2
♣♣
9×10^9 ×16 ×-9 /8^2
♣♣
9×10^9 × -36
= -3.24 e 11
:::: : : : : : : : : : : : : :
Hope you satisfied with my answer
please mark as brainlest as if it helps you
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