Question

2 point charges of 20nu Columb and 80nuColumb are 10 cm apart where will be the electric strength be zero on the line joining charges from 20nuColumb charge is

Answer 1

Answer : 2cm from from 20nu charge.

Expalation :

Let a point charge placed at distance x from charge 20nu and (10-x) from 80nu

The electric field on this charge ,

By 20nu charge is E1=K×20nu÷x^2

& By 80nu charge is E2=K×80nu÷(10-x^2)

Since;

E1=E2

K×20nu÷x^2=K×80nu÷(10-x)^2

On solving ,

x=2cm