Find sides of rectangle whose perimeter is 100m and area 600cm
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Let the length and breadth of the rectangle be x and y respectively,
According to the question,
Area of Rectangle = 600 cm²
==> Length × Breadth = 600
==> x × y = 600
==> x = 600/y ...(1)
Also,
Perimeter of Rectangle = 100 cm
==> 2(x + y) = 100
==> x + y = 50 ...(2)
==> 600 / y + y = 50
==> 600 + y² = 50y
==> y² - 50y + 600 = 0
==> y² + 60y - 10y + 600 = 0
==> y( y + 60) - 10 ( y + 60) = 0
==> (y + 60)(y - 10) = 0
y = -60 or y = 10
Since, length can't be negative so -60 is neglected.
y = 10
Put value of y in (2)
==> x + y = 50
==> x = 50 - y
==> x = 50 - 10
==> x = 40
Hence, The length of the rectangle is 40 cm and breadth of the rectangle is 10 cm.
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