Question

2 point
Q.12. Find :
3 7
8 11​

Answer 1

Solution :-

3/7 + (- 6/11) + (- 8/21) + (5/22)

Taking L.C.M. of the denominators 7, 11, 21 and 22 and then solving it.

L.C.M. of 7, 11, 21 and 22 = 2*3*7*11

= 462

           

= (462/7)*3 - (462/11)*6 - (462/21)*8 + (462/22)*5

= (198/462) - (252/462) - (176/462) + (105/462)

= (303/462) - (428/462)

= (-125/462)