Question

2 points
4. A quadratic polynomial the
sum and product of whose
zeroes are (-7) and 10 is:
O X2 + 5x +12
O X2 + 7x +10
O X2 - 5x +12
O X2 - 7x + 10​

Answer 1

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

TO DETERMINE

A quadratic polynomial the sum and product of whose zeroes are (-7) and 10 respectively

TO FIND

The quadratic polynomial

FORMULA TO BE IMPLEMENTED

The quadratic polynomial whose zeroes are given can be written as

${x}^{2} - ( \: \: sum \: \: of \: \: the \: \: zeros)x \: + \: \: ( \: product \: \: of \: \: the \: \: zeros)$

EVALUATION

The required Quadratic polynomial is

$= {x}^{2} - ( \: \: sum \: \: of \: \: the \: \: zeros)x \: + \: \: ( \: product \: \: of \: \: the \: \: zeros)$

$= {x}^{2} - ( -7)x + ( 10 )$

$= {x}^{2} +7 x +10$

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ADDITIONAL INFORMATION

A general equation of quadratic equation is

$a {x}^{2} + bx + c = 0$

Now one of the way to solve this equation is by SRIDHAR ACHARYYA formula

For any quadratic equation

$a {x}^{2} + bx + c = 0$

The roots are given by

$\displaystyle \: x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac } }{2a}$

Answer 2

Answer:

b

Step-by-step explanation:

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