Math, asked by parishmitanarzari79, 6 months ago

2 points
Q.4 The digit in the tens place of a
two-digit number is 3 more than the
digit in the unit's place. Let the digit
at units place be b. Then the number
is:
10b + 30
O
11b + 3
O
11b + 30
O 10b + 3​

Answers

Answered by raj268798
2

11b+3

Step-by-step explanation:

Digit in unit’s place is b (given).

Digits in ten’s place is 3 more than digit in unit’s place.

So digit in ten’s place is (b+3)

Two digit number = 10* digit in ten’s place + digit in unit’s place.

= 10 *(b+3) + b

= 11*b +3

Answer : The number is 11b +3.

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