2 Poles 30 metre and 15 metre high stand upright in a playground if the poles at 20 m apart the distance between the top most points
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Heya...
Here is your answer -----
As seen in the above diagram, distance between top points = AB
∆ABC = Right angled Triangle right angled at C.
By the Pythagoras Theorem,
=> (AB)^2 = (AC)^2 + (BC)^2
=> x^2 = (15)^2 + (20)^2
=> x^2 = 225 + 400
=> x^2 = 625
=> x = √(625)
=> x = √(5 × 5 × 5 × 5)
=> x = 5 × 5
=> x = 25
AB = x = 25 m
Hence the distance between their top points is 25 metres.
HOPE IT HELPS.....!!!!
Here is your answer -----
As seen in the above diagram, distance between top points = AB
∆ABC = Right angled Triangle right angled at C.
By the Pythagoras Theorem,
=> (AB)^2 = (AC)^2 + (BC)^2
=> x^2 = (15)^2 + (20)^2
=> x^2 = 225 + 400
=> x^2 = 625
=> x = √(625)
=> x = √(5 × 5 × 5 × 5)
=> x = 5 × 5
=> x = 25
AB = x = 25 m
Hence the distance between their top points is 25 metres.
HOPE IT HELPS.....!!!!
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