2. Prove : sec θ √(1 - sin2θ) = 1
Answers
Answered by
1
Step-by-step explanation:
Solution :
Let A = sec θ √(1 - sin2θ) and B = 1.
A = sec θ √(1 - sin2θ)
Because sin2θ + cos2θ = 1, we have
cos2θ = 1 - sin2θ
Then,
A = sec θ √cos2θ
A = sec θ ⋅ cos θ
A = sec θ ⋅ (1/sec θ)
A = sec θ / sec θ
A = 1
A = B (Proved)
Hope this helps you!
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Answered by
0
Answer:
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Step-by-step explanation:
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