Question

2. Prove that { 1 + cot§- sec (¢/2+0)}{ 1 + cot§+ sec (¢/2+0) } = 2
cot§
§=theta and¢=pai​

Answer 1

Answer:

Step-by-step explanation:

{ 1 + cotx - sec( x  + π/2) } { 1 + cotx + sec( x + π/2) }

 

 = {1 + cotx - (- cosecx) } { 1 + cotx + (- cosecx) }

= { 1 + cotx + cosecx} { 1+ cotx - cosecx}

= { ( 1 + cotx) ² - cosec²x}

= 1 + cot²x + 2cotx - cosec²x

= 1 - (cosec²x - cot²x ) + 2cotx

= 1 - 1 + 2cotx             [ cosec²x - cot²x = 1 ]

=2cotx

Hence proved.

Answer 2

Answer:

2 cot x

Step-by-step explanation:

hence proved ok bro