2. Prove that: sin x sin (5 – x) sin (5 + x) = sin3x.
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sinx+sin3x+sin5x+sin7xsinx+7x+sin3x+sin5x[sin(A+B)]sinC+sinD=2sin2C+Dcos2C−DNow,2sin(2x+7x)cos(2x−7x)+2sin(23x+5x)cos(23x−5x)2sin4xcos3x+2sin4xcosx2sin4x(cos3x+cosx)2sin4x[2cos2C+Dcos2C−D]2sin4x[2cos23x+xcos23x−x]2sin4x×2cos2xcosx4sin4xcos2xcosx.
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