Question

In traingle ABC, angle bac =90,
AD perpendicular bc
DE perpendicular AB
DF perpendicular ac
Prove that Area of AEDF=root(AE x eb x AF x fc)
PLEASE Answer this.....
I'll mark u as the branliest.......
I'll follow u..... ​

Answer 1

Do you see that AEDF is a rectangle? Now its area is the multiplication of each breadth and height.

Hint: The breadth and height is related to four triangles.

The ratio of the two sides is equal.

ΔAED ≈ ΔDEB

→ AE : ED = DE : EB

∴ED² = AE × EB, furthermore ED = √AE × EB

ΔAFD ≈ ΔDFC

→ AF : FD = DF : FC

∴FD² = AF × FC, furthermore FD = √AF × FC

ED × FD is the area of the rectangle. Now let's find the multiplication of both equations.

→ ED × FD = √AE × EB × AF × FC therefore proved.

Answer 2

Don't worry it's the correct answer with all steps if u want full marks in it then u must follow only this.

it has a big answer bcoz it is a 3 marks sum

but when u will see it and study it carefully then you will understand it easily

so, Best of luck

you can even ask your teacher

Thank you