Question

2 PUT2QURT2
EXERCISE 6.1
In Fig. 6.13. lines AB and CD intersect at O.
BOE and reflex 2 COE.S.
Fig. 6.13

Answer 1

Answer:

angle BOE = 30° and reflex angle COE = 250°

Step-by-step explanation:

given , line AB and CD intersect at O . angle BOD = angle AOC ( vertically opposite angle) . therefore , angle AOC= 40° . therefore, angle AOC + angle BOE = 70° ; 40°+ angle BOE= 70°; angle BOE= 70°-40°; angle BOE = 30°. here , angle AOC+ angle BOE + angle COE = 180° ; 40°+30°+ angle COE = 180° ; 70°+ angle COE = 180° ; angle COE = 180° - 70° ; angle COE = 110° . therefore, reflex angle COE = 360° - 110° ; reflex angle COE= 250° .

Answer 2

Answer:

here is your answer....

mark as a brainlist...

Step-by-step explanation:

Given, AB is a straight line and OC and OE meets at a point O in AB.

∠ AOC +∠BOE+∠COE=180°

As given ∠AOC+∠BOE=70°

∴70°+∠COE=180°

→∠COE=180°-70°=110°

reflex∠COE=360°-110°=250°

∵CD is a straight line and OE and stand on it.

∠COE+∠BOE+∠BOD=180°

110°+∠BOE+40°=180°

∠BOE=180°-110°-40°

→∠BOE=30°