Question

2) Radius of a circle is 29cm and its distance of the chord from the centre is 21cm. Find the length of the chord.​

Answer 1

here,

r=29cm

distance= 21 cm which is also the chord bisector

Thus ,the chord is twice its base

h²=b²+p²

(29cm)²= b²+(21cm)²

b²= (29cm)²-(21cm)²

b²= (29cm+21cm)(29cm-21cm)

b²= 50cm×8cm

b=√400cm²

=20cm

So the chord is twice the base= 20cm×2= 40cm