Question

2. Ratio of distances covered by object falling freely under gravity in 15, 2nd and 3rd second is
(A) 1:3:5
(B) 1:2:5
(C) 1:4:9
(D) 1:5:9​

Answer 1

According to equation of motion, distance covered in sec.

Sn =u=a/2(2n−1)

Sn =a/2 (2n−1)

∴S1:S2:S3

={2(1)−1}:{2(2)−1}:{2(3)−1}

=1:3:5

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