Question

2. Rationalise the denominators

()1/√3

ii)1/-2+√3
please koi jaldi batao na yr​

Answer 1

Answer:

i) 1/✓3

= 1/✓3*✓3/✓3

= ✓3/3

ii) 1/-2+✓3

= 1/-2+✓3 * -2-✓3/-2-✓3

= -2-✓3/4-3

= -2-✓3/1

= 2-✓3