Question

2
re
It tanx 12
tan (2 + x)
tan (
2x)
Taking LHS
l-tana​

Answer 1

Answer:

Step-by-step explanation:

tan[(π/4) + x] = (1 + tanx) / (1 - tanx)

tan[(π/4) - x] = (1 - tanx) / (1 + tanx)

[(1 + tanx) / (1 - tanx)] ÷ [(1 - tanx) / (1 + tanx)] =

[(1 + tanx) / (1 - tanx)] × [(1 + tanx) / (1 - tanx)] =

(1 + tanx)² / (1 - tanx)² = [(1 + tanx) / (1 - tanx)]²