Question

2. Represent the following situations in the form of quadratic equations :
(1) The area of a rectangular plot is 528 mı?. The length of the plot (in metres) is one
more than twice its breadth. We need to find the length and breadth of the plot.​

Answer 1

let the breadth of the rectangle is X then the length of rectangle is 2x+1 .the product of length and breadth equal to 528.now why solving quadratic( 2x+1)*x=528 we get X

Answer 2

Answer:

LET THE LENGTH BE 'X'

, AND BREATH BE 2X + 1

ATQ/-

AREA OF RECTANGLE = 528

$l \times b \: = 528$

$x \: \times \:( 2x \: + 1) \: = 528$

$2 {x}^{2} + x = 528$

$2 {x}^{2} + x - 528 = 0$

a = 2, b = 1, c = (-528)

NOW we find

By using this formula :

$d \: = {b}^{2} - 4ac$

NOW,

Put the value :

$d \: = {1}^{2} - 4(2)( - 528)$

$d \: = 1 +4224$

$d = 4225$

NOW we find x

And we use formula

$x \: = \frac{ - b \: \frac{ + }{ - } \sqrt{d} }{2a}$

NOW put the value

$x = \frac{ - 1 \frac{ + }{ - } \sqrt{2445} }{2(2)}$

NOW we find two value of x

First in plus and second in minus

FOR PLUS

$x \: = \frac{ - 1 + \sqrt{2445} }{4}$

Solve it