2 Ω resistance coil is to be constructed from a constantan wire of diameter 0.0315 cm.
If the resistivity of constant an is 49x10^(-6) Ωcm, find the length of wire required to construct the coil.
Answers
Answered by
0
Explanation:
Answer
Given, Diameter=0.5mm,resistivity=1.6×10
−8
Ω−m,resistance=10Ω
we know that R=ρ
A
1
⇒1=
ρ
RA
Where A is the area of the cross-section,
=
1.6×10
−8
10×3.14×(
2
0.0005
)
2
=122.7m
Thus the length of the wire is 122.7m
Similar questions